Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 133722 by I want to learn more last updated on 23/Feb/21

Answered by mr W last updated on 23/Feb/21

$$x=28(\tan 40-\tan 20)$$

Answered by bramlexs22 last updated on 23/Feb/21

$$\tan 40°=\frac{\mathrm{CB}}{28}...\left(\mathrm{i}\right)$$$$\tan 20°=\frac{\mathrm{BD}}{28}...\left(\mathrm{ii}\right)$$$$\mathrm{CB}=x+\mathrm{BD}...\left(\mathrm{iii}\right)$$$$\iff x+28\tan 20°=28\tan 40°$$$$\iff x=28\{\frac{2\tan 20°}{1-\tan {}^{2}20°}-\tan 20°\}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com