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Question Number 133923 by bemath last updated on 25/Feb/21

$$\underset{x\to 0}{\lim }\frac{\mid \sin \mathrm{x}\mid }{{\mathrm{x}}^2}=?$$

Answered by EDWIN88 last updated on 25/Feb/21

$${\mathrm{x}}^2=\mid \mathrm{x}{\mid }^2\Rightarrow \underset{x\to 0}{\lim }\frac{\mid \sin \mathrm{x}\mid }{\mid \mathrm{x}\mid }.\frac{1}{\mid \mathrm{x}\mid }=\underset{x\to 0}{\lim }\mid \frac{\sin \mathrm{x}}{\mathrm{x}}\mid .\frac{1}{\mid \mathrm{x}\mid }$$$$=1\times \mathrm{\infty }=\mathrm{\infty }$$

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