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Question Number 137472 by mr W last updated on 03/Apr/21

solve  x^3 −2[x]=5

solvex32[x]=5

Answered by MJS_new last updated on 03/Apr/21

(1)  1<x<2  x^3 =7 ⇒ x=7^(1/3)   (2)  2<x<3  x^3 =9 ⇒ x=9^(1/3)

(1)1<x<2x3=7x=71/3(2)2<x<3x3=9x=91/3

Commented by mr W last updated on 03/Apr/21

thanks sir!

thankssir!

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