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Question Number 134038 by Raxreedoroid last updated on 27/Feb/21

Answered by EDWIN88 last updated on 27/Feb/21

$$\mathrm{V}=2\pi \underset{0}{\stackrel{2}{\int }}(5-\mathrm{x})(8-{\mathrm{x}}^3)\mathrm{dx}$$$$\mathrm{V}=2\pi \underset{0}{\stackrel{2}{\int }}(40-{5\mathrm{x}}^3-8\mathrm{x}+{\mathrm{x}}^4)\mathrm{dx}$$$$\mathrm{V}=2\pi {[40\mathrm{x}-\frac{{5\mathrm{x}}^4}{4}-{4\mathrm{x}}^2+\frac{{\mathrm{x}}^5}{5}]}_0^2$$$$\mathrm{V}=2\pi [80-20-16+\frac{32}{5}]$$$$\mathrm{V}=2\pi (44+\frac{32}{5})=2\pi \left(\frac{220+32}{5}\right)=\frac{504\pi }{5}$$

Commented by Raxreedoroid last updated on 27/Feb/21

$$\mathrm{Thanks}\mathrm{sir}...$$

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