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Question Number 134145 by EDWIN88 last updated on 28/Feb/21

Commented by Ñï= last updated on 28/Feb/21

$A n y t i m e a n y 2 h a n d s n o c o i n c i d e . I r e m e m b e r .$
Commented by mr W last updated on 28/Feb/21

$p l e a s e e x p l a i n w h a t y o u m e a n s i r!$
	Answered by mr W last updated on 28/Feb/21

	$a s s u m e d t h e h a n d s m o v e u n i f o r m l y .$ $s a y x m i n u t e s p a s t 2 .$ $p o s i t i o n o f h o u r h a n d : 10 + \frac{x}{60} \times 5$ $p o s i t i o n o f m i n u t e h a n d : x$ $10 + \frac{x}{60} \times 5 = x$ $x = \frac{120}{11} = 10 \frac{10}{11}$ $\Rightarrow (a)$
	Commented by mr W last updated on 28/Feb/21

	$o l d s t y l e c l o c k s h a v e h a n d s w h i c h$ ${d o n}^{'} t m o v e u n i f o r m l y, b u t s t e p w i s e,$ $s e e Q 17449$
	Commented by EDWIN88 last updated on 28/Feb/21

	$yes . . thanks$
	Answered by bobhans last updated on 28/Feb/21

	$∴ The time when hands be together$ $= (5 \times n \times \frac{60}{55}) mins past n o^{'} clock$ $Here n = 2$ $= 5 \times 2 \times \frac{60}{55} = \frac{120}{11} = 10 \frac{10}{11} mins past 2$
	Commented by EDWIN88 last updated on 28/Feb/21

	$thanks$
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