Question Number 134232 by liberty last updated on 01/Mar/21 | ||
$$ \\ $$ In how many ways can 5 men, 4 women, and 3 children be arranged in a row of 12 seats if the children sit together?\\n | ||
Answered by mr W last updated on 01/Mar/21 | ||
$$\mathrm{10}!\mathrm{3}!=\mathrm{21}\:\mathrm{772}\:\mathrm{800} \\ $$ | ||
Answered by Ñï= last updated on 01/Mar/21 | ||
$${MMMM}\underset{{take}\:{as}\:\mathrm{1}\:{people}} {\underbrace{{CCC}}WWMWW} \\ $$ $${all}\:\mathrm{10}\:{people} \\ $$ $${A}_{\mathrm{10}} ^{\mathrm{10}} ×{A}_{\mathrm{3}} ^{\mathrm{3}} =\mathrm{10}!×\mathrm{3}! \\ $$ | ||