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Question Number 134237 by mathlove last updated on 01/Mar/21

$$f\left(x\right)=\frac{2x^{100!}}{(100!)!}+x^{100}+1$$$$faind\frac{d^{100!}f\left(x\right)}{{dx}^{100!}}=?$$

Answered by malwan last updated on 01/Mar/21

$$\frac{d^{100!}f\left(x\right)}{{dx}^{100!}}=\frac{2\times (100!)!}{(100!)!}+0+0=2$$

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