Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 134255 by shaker last updated on 01/Mar/21

Commented by Dwaipayan Shikari last updated on 01/Mar/21

$$C_m^n(n<m)isnotdefined$$

Commented by mr W last updated on 01/Mar/21

$$ithinkhemeans{C}_n^m(n<m).insome$$$$countriespeoplewrite{C}_m^{n}insteadof$$$$C_n^m.$$

Answered by EDWIN88 last updated on 01/Mar/21

$$\mathrm{let}:\mathrm{T}=\frac{\frac{100\times 99}{2\times 1}+\frac{1000\times 999}{2\times 1}}{\frac{1000\times 999}{2\times 1}+\frac{100\times 99}{2\times 1}}=1$$$$\mathrm{let}\mathrm{Q}=\frac{1+\frac{7\times 6\times 5}{3\times 2\times 1}+\frac{7\times 6\times 5}{3\times 2\times 1}-\frac{8\times 7\times 6\times 5}{4\times 3\times 2\times 1}}{1+\frac{10\times 9\times 8\times 7\times 6}{5\times 4\times 3\times 2\times 1}+\frac{10\times 9\times 8\times 7}{4\times 3\times 2\times 1}-\frac{11\times 10\times 9\times 8\times 7}{5\times 4\times 3\times 2\times 1}}$$

Answered by Ñï= last updated on 01/Mar/21

$$A=\frac{C_{100}^2+C_{1000}^2}{C_{1000}^2+C_{100}^2}+\frac{1+C_8^4-C_8^4}{1+C_{11}^6-C_{11}^6}$$$$=1+1$$$$=2$$$$C_n^k+C_n^{k-1}=C_{n+1}^k\iff \left(\begin{array}{c}n\\ k\end{array}\right)+\left(\begin{array}{c}n\\ k-1\end{array}\right)=\left(\begin{array}{c}n+1\\ k\end{array}\right)$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com