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Question Number 134328 by BHOOPENDRA last updated on 02/Mar/21

express f(x)=x as a sine series   in 0<x<π?

expressf(x)=xasasineseries in0<x<π?

Answered by Dwaipayan Shikari last updated on 02/Mar/21

log(1+e^(ix) )=log((√(2+2sinx)))+itan^(−1) ((sinx)/(cosx+1))  (cosx−((cos2x)/2)+((cos3x)/3)−((cos4x)/4)+...)+i(sinx−((sin2x)/2)+((sin3x)/3)−..)  =log((√(2+2sinx)))+itan^(−1) ((2sin(x/2)cos(x/2))/(2cos^2 (x/2)))  sinx−((sin2x)/2)+((sin3x)/3)−((sin4x)/4)+...=tan^(−1) (tan(x/2))  (x/2)=sinx−((sin2x)/2)+((sin3x)/3)−((sin4x)/4)+...

log(1+eix)=log(2+2sinx)+itan1sinxcosx+1 (cosxcos2x2+cos3x3cos4x4+...)+i(sinxsin2x2+sin3x3..) =log(2+2sinx)+itan12sinx2cosx22cos2x2 sinxsin2x2+sin3x3sin4x4+...=tan1(tanx2) x2=sinxsin2x2+sin3x3sin4x4+...

Commented byDwaipayan Shikari last updated on 02/Mar/21

But for x=π it doesn′t hold true. 0<x<π  for example  ((((π/2)))/2)=sin((π/2))−((sin(π))/2)+((sin(((3π)/2)))/3)−((sin(2π))/4)+..  (π/4)=1−(1/3)+(1/5)−(1/7)+...

Butforx=πitdoesntholdtrue.0<x<π forexample (π2)2=sin(π2)sin(π)2+sin(3π2)3sin(2π)4+.. π4=113+1517+...

Commented byBHOOPENDRA last updated on 02/Mar/21

thanks sir

thankssir

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