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Question Number 134335 by bramlexs22 last updated on 02/Mar/21

$$ \\ $$ Two Team A&B of workers at a bridge site. Each team consist of W workers. On a particular day, a worker was shifted from team A to team B . Now if the ratio of the amount of workdone by teamA in (W+1) he & by teamB in (W+2) hr is 10:12 rsp. Find W?\\n

Answered by mr W last updated on 02/Mar/21

team A: W−1 workers  works done in W+1 hours=(W−1)(W+1)    team B: W+1 workers  works done in W+2 hours=(W+1)(W+2)    (((W−1)(W+1))/((W+1)(W+2)))=((10)/(12))=(5/6)  6W−6=5W+10  ⇒W=16

$${team}\:{A}:\:{W}−\mathrm{1}\:{workers} \\ $$ $${works}\:{done}\:{in}\:{W}+\mathrm{1}\:{hours}=\left({W}−\mathrm{1}\right)\left({W}+\mathrm{1}\right) \\ $$ $$ \\ $$ $${team}\:{B}:\:{W}+\mathrm{1}\:{workers} \\ $$ $${works}\:{done}\:{in}\:{W}+\mathrm{2}\:{hours}=\left({W}+\mathrm{1}\right)\left({W}+\mathrm{2}\right) \\ $$ $$ \\ $$ $$\frac{\left({W}−\mathrm{1}\right)\left({W}+\mathrm{1}\right)}{\left({W}+\mathrm{1}\right)\left({W}+\mathrm{2}\right)}=\frac{\mathrm{10}}{\mathrm{12}}=\frac{\mathrm{5}}{\mathrm{6}} \\ $$ $$\mathrm{6}{W}−\mathrm{6}=\mathrm{5}{W}+\mathrm{10} \\ $$ $$\Rightarrow{W}=\mathrm{16} \\ $$

Commented bybramlexs22 last updated on 02/Mar/21

i got W=4.  both team A and B have the same  worker

$$\mathrm{i}\:\mathrm{got}\:\mathrm{W}=\mathrm{4}. \\ $$ $$\mathrm{both}\:\mathrm{team}\:\mathrm{A}\:\mathrm{and}\:\mathrm{B}\:\mathrm{have}\:\mathrm{the}\:\mathrm{same} \\ $$ $$\mathrm{worker} \\ $$

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