Question Number 134627 by bobhans last updated on 05/Mar/21
$$\mathcal{ALGEBRA} \\ $$ If Bobby walks to school at 50m/min. He will be late for 3 minutes. If he walks 60 m/min, he arrives at school early by 2 mins. What is the distance between Bobby's home and school?\\n
Answered by som(math1967) last updated on 06/Mar/21
![(x/(50)) −(x/(60))=5 [x=dist. between Bobby′shome an school] ⇒((6x−5x)/(300))=5 ⇒x=1500 Distance between Bobby′s home and school=1500m](Q134638.png)
$$\:\:\frac{{x}}{\mathrm{50}}\:−\frac{{x}}{\mathrm{60}}=\mathrm{5}\:\:\:\:\:\left[{\color{mathred}{x}}\color{mathred}{=}{\color{mathred}{d}\color{mathred}{i}\color{mathred}{s}\color{mathred}{t}}\color{mathred}{.}\color{mathred}{\:}{\color{mathred}{b}\color{mathred}{e}\color{mathred}{t}\color{mathred}{w}\color{mathred}{e}\color{mathred}{e}\color{mathred}{n}}\right. \\ $$ $$\left.\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}\color{mathred}{\:}{\color{mathred}{B}\color{mathred}{o}\color{mathred}{b}\color{mathred}{b}\color{mathred}{y}}\color{mathred}{'}{\color{mathred}{s}}\boldsymbol{{\color{mathred}{h}\color{mathred}{o}\color{mathred}{m}\color{mathred}{e}}}\color{mathred}{\:}\boldsymbol{{\color{mathred}{a}\color{mathred}{n}}}\color{mathred}{\:}\boldsymbol{{\color{mathred}{s}\color{mathred}{c}\color{mathred}{h}\color{mathred}{o}\color{mathred}{o}\color{mathred}{l}}}\right] \\ $$ $$\Rightarrow\frac{\mathrm{6}{x}−\mathrm{5}{x}}{\mathrm{300}}=\mathrm{5} \\ $$ $$\Rightarrow{x}=\mathrm{1500} \\ $$ $${Distance}\:{between}\:{Bobby}'{s} \\ $$ $${home}\:{and}\:{school}=\mathrm{1500}{m} \\ $$