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Question Number 134689 by benjo_mathlover last updated on 06/Mar/21
2289+1217+1=2a1+2a2+2a3+...+2akFindthevalueofk.
Answered by EDWIN88 last updated on 06/Mar/21
Let217=y⇒y17+1y+1=y16−y15+y14−y13+y12−y11+...+1=y15(y−1)+y13(y−1)+y11(y−1)+...+y(y−1)+1=(y15+y13+y11+y9+...+y)(y−1)+1=(2255+2221+2187+...+217)(217−1)+1=(2255+2221+2187+...+217)⏟(216+215+214+...+2+1)178+1sowegetk=8×17+1=137
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