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Question Number 134713 by bramlexs22 last updated on 06/Mar/21

geometry

geometry All the edges of a regular square pyramid have a length of 8. What is the volume?\n

Answered by john_santu last updated on 06/Mar/21

Reguler square pyramid already  a regular quadrilateral.  An equilateral triangle is two of  mirrored acroos the long leg  30°−60°−90° right the triangles  with sides in the ratio 1 : (√3) : 2 ,   The altitude of face triangle is  ((√3)/2) × 8 = 4(√3) . That triangle is   tilted in so the top vertex is over   the center of square 4 units from the  edge : h^2  + 4^2  = (4(√3))^2 ⇒h=4(√2)  so the Volume = (1/3)A.h = (1/3)×8^2  × 4(√2)  Vol = ((256(√2) )/3) units^3  •

Regulersquarepyramidalready aregularquadrilateral. Anequilateraltriangleistwoof mirroredacroosthelongleg 30°60°90°rightthetriangles withsidesintheratio1:3:2, Thealtitudeoffacetriangleis 32×8=43.Thattriangleis tiltedinsothetopvertexisover thecenterofsquare4unitsfromthe edge:h2+42=(43)2h=42 sotheVolume=13A.h=13×82×42 Vol=25623units3

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