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Question Number 120614 by TANMAY PANACEA last updated on 01/Nov/20

$T r i g o n o m e t r y$
Commented by TANMAY PANACEA last updated on 01/Nov/20

Commented by TANMAY PANACEA last updated on 01/Nov/20

Commented by TANMAY PANACEA last updated on 01/Nov/20

Commented by TANMAY PANACEA last updated on 01/Nov/20

Commented by Dwaipayan Shikari last updated on 01/Nov/20

$t a n \frac{π}{9} + 4 s i n \frac{π}{9}$ $= \frac{1}{c o s 20 °} (s i n 20 ° + 4 c o s 20 s i n 20 °)$ $= \frac{1}{c o s 20 °} (s i n 20 ° + 2 s i n 40 °)$ $= \frac{1}{c o s 20 °} (2 s i n 30 ° c o s 10 ° + s i n 40 °)$ $= \frac{1}{c o s 20 °} (s i n 80 ° + s i n 40 °)$ $= \frac{1}{c o s 20 °} (2 s i n 60 ° c o s 20 °)$ $= \sqrt{3}$
Commented by Dwaipayan Shikari last updated on 01/Nov/20

$t a n (\frac{2 π}{9}) - 4 s i n (\frac{2 π}{9})$ $= \frac{1}{c o s 40 °} (s i n 40 ° - 4 s i n 40 ° c o s 40 °$ $= \frac{1}{c o s 40 °} (s i n 40 ° - 2 s i n 80 °)$ $= - \frac{1}{c o s 40 °} (2 c o s 60 ° s i n 20 ° + s i n 80 °)$ $= - \frac{1}{c o s 40 °} (2 s i n 50 c o s 30)$ $= - \sqrt{3}$
Commented by TANMAY PANACEA last updated on 01/Nov/20

$t h a n k y o u$
Commented by TANMAY PANACEA last updated on 01/Nov/20

$t h a n k y o u$
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