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Question Number 134839 by SOMEDAVONG last updated on 07/Mar/21

$$\mathrm{Solve},{\mathrm{S}}_{\mathrm{n}}=1+2\times 2+3\times 2^2+4\times 2^3+...+\mathrm{n}\times 2^{\mathrm{n}-1}.$$

Commented by mr W last updated on 07/Mar/21

$$seeQ134200$$

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