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Question Number 134872 by bemath last updated on 08/Mar/21

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Trygonometri What is the value of cosA if cosA+3sinA=2?\n

Answered by EDWIN88 last updated on 08/Mar/21

We have sin A = ± (√(1−cos ^2 A))  then 3sin A = 2−cos A , square to get  9sin ^2 A = (2−cos A)^2   9−9cos ^2 A = cos ^2 A−4cos A+4   10cos ^2 A−4cos A−5= 0    cos A = ((4± (√(16+4.50)))/(20)) = ((4 ± 2(√(54)))/(20))   cos A = ((2±3(√6))/(10))

WehavesinA=±1cos2A then3sinA=2cosA,squaretoget 9sin2A=(2cosA)2 99cos2A=cos2A4cosA+4 10cos2A4cosA5=0 cosA=4±16+4.5020=4±25420 cosA=2±3610

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