The two side of rectangle are 2x and (!5−2x) units respectively For what value of x the area of rectangle will be maximum?


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Question Number 134874 by bemath last updated on 08/Mar/21

$The two side of rectangle are$ $2 x and (! 5 - 2 x) units respectively$ $For what value of x the area of$ $rectangle will be maximum ?$
Commented by Ñï= last updated on 08/Mar/21

$! 5 = 5! (1 - 1! + \frac{1}{2!} - \frac{1}{3!} + \frac{1}{4!} - \frac{1}{5!}) = 44$ $I g o t i t .$
	Answered by mr W last updated on 08/Mar/21

	$A = (2 x) \times (5 - 2 x) ⩽ \frac{2 x + (5 - 2 x)}{2} = \frac{5}{2}$ $m a x . = \frac{5}{2} w h e n 2 x = 5 - 2 x, i . e x = \frac{5}{4}$
	Commented by bemath last updated on 08/Mar/21

	$this (! 5 - 2 x) sir ?$
	Commented by mr W last updated on 08/Mar/21

	$w h a t d o y o u w a n t t o s a y w i t h! 5 ? i f$ $y o u m e a n! 5 = 44, y o u c a n r e p l a c e 5$ $w i t h 44 .$
	Commented by bemath last updated on 08/Mar/21

	in the book it says sir. ha ha ha
	Commented by Ñï= last updated on 08/Mar/21

	$! 5 = 5 \times 6 \times 7 \times 8 \times 9 ?$
	Commented by mr W last updated on 08/Mar/21

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