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Question Number 134912 by bramlexs22 last updated on 08/Mar/21
Given{a+b=5abb+c=7bcc+a=6acwherea,b,c≠0.Findabc
Answered by Ñï= last updated on 08/Mar/21
1a+1b=5⇔A+B=51b+1c=7⇔B+C=71a+1c=6⇔A+C=6⇒A=2B=3C=4⇒abc=1ABC=124
Commented by Rasheed.Sindhi last updated on 10/Mar/21
Nicesir!
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