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Question Number 134931 by metamorfose last updated on 08/Mar/21
naninteger,∫101tn+1dt=...??
Answered by Dwaipayan Shikari last updated on 08/Mar/21
∫011tn+1dt=∫011−tn1−t2ndtt2n=u=12n∫01t1−2n−t1−n1−udu=12n∫01u12n−1−u12n−121−udu=12nψ(12n+12)−12nψ(12n)
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