Math Question and Answers


Question and Answers Forum

All Questions Topic List
Logic Questions
Previous in All Question Next in All Question
Previous in Logic Next in Logic
Question Number 134948 by rexford last updated on 08/Mar/21

Commented by bobhans last updated on 09/Mar/21

$what definition \vec{a} \land \vec{b} ?$
Commented by rexford last updated on 09/Mar/21

$c r o s s p r o d u c t$
	Answered by bramlexs22 last updated on 09/Mar/21
	$a^→ .b^→ = 0 , a^→ ⊥ b^→ a^→ .c^→ = 0 , a^→ ⊥ c^→ → { ((∣a^→ ×b^→ ∣ = ∣a^→ ∣.∣b^→ ∣.sin 90°=1)),((∣a^→ ×c^→ ∣ = ∣a^→ ∣.∣c^→ ∣.sin 90°=1)) :} now ∣a^→ ×b^→ −a^→ ×c^→ ∣ = (√(1^2 +1^2 −2.1.1 cos 180°)) = (√(2+2)) = 2$
	$\vec{a} . \vec{b} = 0, \vec{a} ⊥ \vec{b}$ $\vec{a} . \vec{c} = 0, \vec{a} ⊥ \vec{c}$ $\to {\begin{cases} ∣ \vec{a} \times \vec{b} ∣ = ∣ \vec{a} ∣ . ∣ \vec{b} ∣ . \sin 90 ° = 1 \\ ∣ \vec{a} \times \vec{c} ∣ = ∣ \vec{a} ∣ . ∣ \vec{c} ∣ . \sin 90 ° = 1 \end{cases}$ $now ∣ \vec{a} \times \vec{b} - \vec{a} \times \vec{c} ∣ = \sqrt{1^{2} + 1^{2} - 2.1.1 \cos 180 °}$ $= \sqrt{2 + 2} = 2$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum