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Question Number 135101 by BHOOPENDRA last updated on 10/Mar/21

Commented by BHOOPENDRA last updated on 10/Mar/21

$f i n d m o m e n t o f i n e r t i a ?$
Commented by mr W last updated on 15/Mar/21

$m o i i s a l w a y s i n r e l a t i o n t o a n a x i s .$ $w i t h o u t s a y i n g a b o u t w h i c h a x i s,$ $t h e r e i s n o a n s w e r p o s s i b l e .$
Commented by BHOOPENDRA last updated on 16/Mar/21

$a b o u t b o t h a x i s X a n d Y$
	Answered by mr W last updated on 17/Mar/21

	Commented by mr W last updated on 17/Mar/21

	$s = \frac{70 \times 10 \times 5 + 60 \times 10 \times (10 + 30)}{70 \times 10 + 60 \times 10}$ $\approx 19.538 m m$ $I_{x} = \frac{70 \times 10^{3}}{12} + 70 \times 10 \times {(19.538 - 5)}^{2}$ $+ \frac{10 \times 60^{3}}{12} + 10 \times 60 \times {(40 - 19.538)}^{2}$ $\approx 584997 {m m}^{4}$ $I_{y} = \frac{10 \times 70^{3}}{12} + \frac{60 \times 10^{3}}{12}$ $\approx 290833 {m m}^{4}$
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