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Question Number 135211 by benjo_mathlover last updated on 11/Mar/21

$$\mathrm{Find}\mathrm{minimum}\mathrm{value}\mathrm{of}\mathrm{function}$$$$\mathrm{f}\left(\mathrm{x}\right)=\frac{{4\mathrm{x}}^2+8\mathrm{x}+13}{6(1+\mathrm{x})}$$

Commented by mr W last updated on 11/Mar/21

$$\underset{x\to -1^{-}}{\lim }f\left(x\right)=-\mathrm{\infty }$$$$\underset{x\to -1^{+}}{\lim }f\left(x\right)=+\mathrm{\infty }$$$$\Rightarrow thereisnominimumandno$$$$maxinumforf\left(x\right)!$$

Commented by benjo_mathlover last updated on 11/Mar/21

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