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Question Number 135211 by benjo_mathlover last updated on 11/Mar/21

Find minimum value of function  f(x) = ((4x^2 +8x+13)/(6(1+x)))

Findminimumvalueoffunctionf(x)=4x2+8x+136(1+x)

Commented by mr W last updated on 11/Mar/21

lim_(x→−1^− ) f(x)=−∞  lim_(x→−1^+ ) f(x)=+∞  ⇒there is no minimum and no  maxinum for f(x)!

limx1f(x)=limx1+f(x)=+thereisnominimumandnomaxinumforf(x)!

Commented by benjo_mathlover last updated on 11/Mar/21

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