Question Number 135213 by mr W last updated on 11/Mar/21
Commented by mr W last updated on 11/Mar/21
$${if}\:{the}\:{truck}\:{can}\:{start}\:{with}\:{an} \\ $$$${acceleration}\:{a},\:{find}\:{the}\:{friction} \\ $$$${coefficient}\:{between}\:{tires}\:{and}\:{ground}. \\ $$
Commented by mr W last updated on 12/Mar/21
$${M}_{\mathrm{2}} =\frac{{L}_{\mathrm{1}} {M}}{{L}_{\mathrm{1}} +{L}_{\mathrm{2}} } \\ $$$${M}_{\mathrm{1}} =\frac{{L}_{\mathrm{2}} {M}}{{L}_{\mathrm{1}} +{L}_{\mathrm{2}} } \\ $$$$\mu\left({M}_{\mathrm{2}} −{M}_{\mathrm{1}} \right){g}={Ma} \\ $$$$\Rightarrow\mu=\frac{{L}_{\mathrm{1}} +{L}_{\mathrm{2}} }{{L}_{\mathrm{1}} −{L}_{\mathrm{2}} }×\frac{{a}}{{g}} \\ $$