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Question Number 135213 by mr W last updated on 11/Mar/21

Commented by mr W last updated on 11/Mar/21

$i f t h e t r u c k c a n s t a r t w i t h a n$ $a c c e l e r a t i o n a, f i n d t h e f r i c t i o n$ $c o e f f i c i e n t b e t w e e n t i r e s a n d g r o u n d .$
Commented by mr W last updated on 12/Mar/21

$M_{2} = \frac{L_{1} M}{L_{1} + L_{2}}$ $M_{1} = \frac{L_{2} M}{L_{1} + L_{2}}$ $μ (M_{2} - M_{1}) g = M a$ $\Rightarrow μ = \frac{L_{1} + L_{2}}{L_{1} - L_{2}} \times \frac{a}{g}$
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