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Question Number 135215 by mnjuly1970 last updated on 11/Mar/21
.....calculuspreliminary....Q:f(x)=2x−2−x⇒f−1(x)=???solution:y=2x−2−x.....y=22x−12x⇒22x−y2x−1=0(∗)...::2x=t⇒t>0...✓....(∗)→...t2−ty−1=0....Δ=y2+4>0...✓...t=y+y2+42......::2x=y+y2+42⇒takinglogbothsides....x:=log2(y+y2+42)f−1(x)=log2(x+x2+42)✓✓.........................
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