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Question Number 135253 by otchereabdullai@gmail.com last updated on 11/Mar/21

Commented by mr W last updated on 11/Mar/21

∠YXZ=90° ⇒YX=(√(5^2 −3^2 ))=4  area of ΔXYZ=((YX×XZ)/2)=((YZ×XN)/2)  ⇒XN=((4×3)/5)=((12)/5)

$$\angle{YXZ}=\mathrm{90}°\:\Rightarrow{YX}=\sqrt{\mathrm{5}^{\mathrm{2}} −\mathrm{3}^{\mathrm{2}} }=\mathrm{4} \\ $$$${area}\:{of}\:\Delta{XYZ}=\frac{{YX}×{XZ}}{\mathrm{2}}=\frac{{YZ}×{XN}}{\mathrm{2}} \\ $$$$\Rightarrow{XN}=\frac{\mathrm{4}×\mathrm{3}}{\mathrm{5}}=\frac{\mathrm{12}}{\mathrm{5}} \\ $$

Commented by otchereabdullai@gmail.com last updated on 11/Mar/21

May the Almigthy Allah add more  years to your age prof W

$$\mathrm{May}\:\mathrm{the}\:\mathrm{Almigthy}\:\mathrm{Allah}\:\mathrm{add}\:\mathrm{more} \\ $$$$\mathrm{years}\:\mathrm{to}\:\mathrm{your}\:\mathrm{age}\:\mathrm{prof}\:\mathrm{W} \\ $$

Commented by mr W last updated on 11/Mar/21

shukran! al−hamdu li−lah!

$${shukran}!\:{al}−{hamdu}\:{li}−{lah}! \\ $$

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