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Question Number 135298 by Ahmed1hamouda last updated on 12/Mar/21
Answered by mr W last updated on 12/Mar/21
1z=x+yi1z=1x+yi=x−yix2+y2Re(1z)=xx2+y2⩽12x2+y2⩾2x(x−1)2+y2⩾1
Commented by mr W last updated on 12/Mar/21
2z=x+yiz−=x−yiz−z−=2yiz−z¯2i=y=Im(z)
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