Question and Answers Forum

All Question   Topic List

Question Number 135420 by liberty last updated on 13/Mar/21

$$Algebra$$ Pipe A can fill a tank in two hours and pipe B can fill it in half the time it takes pipe C to empty it. When all 3 are opened, it takes 1.5 hours to fill the pool how much time is required for pipe 'C to empty the tank?\n

Answered by john_santu last updated on 13/Mar/21

$$\left(1\right)pipeA\Rightarrow V_1=\frac{W}{2}$$ $$\left(2\right)pipeC\Rightarrow V_2=\frac{W}{a}$$ $$\left(3\right)pipeB\Rightarrow V_3=\frac{W}{a/2}$$ $$\left(4\right)Whenall3pipeareopened$$ $$\Rightarrow \frac{W}{V_1+V_2+V_3}=\frac{3}{2}$$ $$\Rightarrow \frac{W}{\frac{W}{2}+\frac{W}{a}+\frac{2W}{a}}=\frac{3}{2}$$ $$\Rightarrow \frac{1}{2}+\frac{3}{a}=\frac{2}{3};\frac{3}{a}=\frac{1}{6}$$ $$wegeta=18hour$$ $$$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com