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Question Number 135780 by bramlexs22 last updated on 15/Mar/21

If g(0)=2 , g ′(0)=1 and   f(x) = e^(2x) g(x). What the value  of f^(−1) (2).

$${If}\:{g}\left(\mathrm{0}\right)=\mathrm{2}\:,\:{g}\:'\left(\mathrm{0}\right)=\mathrm{1}\:{and}\: \\ $$$${f}\left({x}\right)\:=\:{e}^{\mathrm{2}{x}} {g}\left({x}\right).\:{What}\:{the}\:{value} \\ $$$${of}\:{f}^{−\mathrm{1}} \left(\mathrm{2}\right). \\ $$

Commented by bramlexs22 last updated on 16/Mar/21

  😎😅😎

$$ \\ $$😎😅😎

Answered by benjo_mathlover last updated on 16/Mar/21

(1) f(0) = 1.2 ⇒f^(−1) (2)=0   🤔

$$\left(\mathrm{1}\right)\:{f}\left(\mathrm{0}\right)\:=\:\mathrm{1}.\mathrm{2}\:\Rightarrow{f}^{−\mathrm{1}} \left(\mathrm{2}\right)=\mathrm{0}\: \\ $$🤔

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