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Question Number 135840 by abdurehime last updated on 16/Mar/21

Answered by liberty last updated on 16/Mar/21

from p⇒ ∽q False we get  { ((p : T)),((q : T)) :}  so the following statements is  True : (p ∼q)⇔(∼r r)  answer : C

$${from}\:{p}\Rightarrow\:\backsim{q}\:{False}\:{we}\:{get}\:\begin{cases}{{p}\::\:{T}}\\{{q}\::\:{T}}\end{cases} \\ $$$${so}\:{the}\:{following}\:{statements}\:{is} \\ $$$${True}\::\:\left({p} \sim{q}\right)\Leftrightarrow\left(\sim{r} {r}\right) \\ $$$${answer}\::\:{C} \\ $$

Commented by abdurehime last updated on 16/Mar/21

? where is the value of r???

$$?\:\mathrm{where}\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{r}??? \\ $$

Commented by abdurehime last updated on 16/Mar/21

how to evaluate ()

$$\mathrm{how}\:\mathrm{to}\:\mathrm{evaluate}\:\left(\right) \\ $$

Commented by liberty last updated on 16/Mar/21

you know the value : ∼r  r : False

$${you}\:{know}\:{the}\:{value}\::\:\sim{r}\: {r}\::\:{False} \\ $$

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