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Question Number 136002 by physicstutes last updated on 17/Mar/21

A man has a set of 5 balls, in which 3 are red and 2 are blue  what are the number of ways these 5 balls can be arranged in a   line.

$$\mathrm{A}\:\mathrm{man}\:\mathrm{has}\:\mathrm{a}\:\mathrm{set}\:\mathrm{of}\:\mathrm{5}\:\mathrm{balls},\:\mathrm{in}\:\mathrm{which}\:\mathrm{3}\:\mathrm{are}\:\mathrm{red}\:\mathrm{and}\:\mathrm{2}\:\mathrm{are}\:\mathrm{blue} \\ $$$$\mathrm{what}\:\mathrm{are}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{ways}\:\mathrm{these}\:\mathrm{5}\:\mathrm{balls}\:\mathrm{can}\:\mathrm{be}\:\mathrm{arranged}\:\mathrm{in}\:\mathrm{a}\: \\ $$$$\mathrm{line}. \\ $$

Answered by liberty last updated on 17/Mar/21

((5!)/(2!.3!))

$$\frac{\mathrm{5}!}{\mathrm{2}!.\mathrm{3}!} \\ $$

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