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Question Number 13627 by tawa tawa last updated on 21/May/17

Answered by ajfour last updated on 21/May/17

$$\frac{1}{\lambda }=R(\frac{1}{n_2^2}-\frac{1}{n_1^2})$$$$\frac{1}{\lambda }=R(\frac{1}{4}-\frac{1}{9})$$$$\lambda =\frac{36}{5R}=\frac{36}{5(1.097\times {10}^7{m}^{-1})}$$$$\lambda =\frac{3600}{5\times 1.097}nm=\frac{720}{1.097}nm$$$$\lambda \approx 656nm.$$

Commented by tawa tawa last updated on 21/May/17

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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