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Question Number 136481 by BHOOPENDRA last updated on 22/Mar/21

∫_0 ^((50π)/3) ∣sinx∣dx

050π3sinxdx

Answered by MJS_new last updated on 22/Mar/21

∫_0 ^(50π/3) ∣sin x∣dx=33∫_0 ^(π/2) sin x dx+∫_(π/2) ^(2π/3) sin x dx=((67)/2)

50π/30sinxdx=33π/20sinxdx+2π/3π/2sinxdx=672

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