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Question Number 136741 by JulioCesar last updated on 25/Mar/21

Answered by Dwaipayan Shikari last updated on 25/Mar/21

$$\underset{x\to 0}{\lim }\frac{x!-1}{x}=\frac{\mathrm{\Gamma }(x+1)-1}{x}=\frac{{\mathrm{\Gamma }}^{\prime }(x+1)}{1}={\mathrm{\Gamma }}^{\prime }\left(1\right)=-\gamma$$

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