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Question Number 136866 by mohammad17 last updated on 27/Mar/21

Commented by mohammad17 last updated on 27/Mar/21

$$helpmesir$$

Commented by mohammad17 last updated on 27/Mar/21

$$helpmesirpleaseiwantQ2ajust$$

Answered by Olaf last updated on 27/Mar/21

$$1)\mathrm{A})$$$$\mathrm{Re}=\frac{{VL}_c}{\nu }\left(\mathrm{Reynolds}\mathrm{number}\right)$$$$\left[\mathrm{Re}\right]=\frac{[m.s^{-1}]\times \left[m\right]}{[m^2.s^{-1}]}=\left[\frac{m^2.s^{-1}}{m^2.s^{-1}}\right]:\mathrm{dimensionless}$$$$\mathrm{Sp}.\mathrm{g}=\frac{\rho }{{\rho }_{purewater}}(\mathrm{or}\mathrm{Sp}.\mathrm{gr}\mathrm{specific}\mathrm{gravity})$$$$[\mathrm{Sp}.\mathrm{g}]=\frac{[kg.m^{-3}]}{[kg.m^{-3}]}=\left[\frac{kg.m^{-3}}{kg.m^{-3}}\right]:\mathrm{dimensionless}$$

Answered by Olaf last updated on 27/Mar/21

$$2)$$$$\mathrm{Q}=1,95\times {10}^{-3}{\mathrm{ft}}^3/s=5,52\times {10}^{-5}{m}^3/s$$$$\mathrm{D}=1\mathrm{in}=0,0254m$$$$\nu =1\mathrm{c}.\mathrm{p}={10}^{-3}\mathrm{Pa}.s$$$$\mathrm{V}=\frac{\mathrm{Q}}{\mathrm{S}}=\frac{\mathrm{Q}}{\pi \frac{{\mathrm{D}}^2}{4}}=\frac{5,52\times {10}^{-3}}{\frac{\pi }{4}\times {(0,0254)}^2}=11,73m/s$$$$\mathrm{Re}=\frac{\mathrm{VD}}{\nu }=\frac{11,73\times 0,0254}{{10}^{-3}}=297,9$$$$0<\mathrm{Re}<2000\Rightarrow \mathrm{laminar}\mathrm{flow}$$

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