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Question Number 136892 by Rayan1997 last updated on 27/Mar/21
∫d2ydx2dy
Answered by Olaf last updated on 27/Mar/21
F(x)=∫d2ydx2dyF(x)=∫(d2ydx2)(dydx)dxF(x)=∫y″y′dxF(x)=12y′2+C
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