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Question Number 136929 by liberty last updated on 27/Mar/21
∫eln(sin−1x)1−x2dx=?
Answered by Dwaipayan Shikari last updated on 27/Mar/21
∫elog(sin−1x)1−x2dxsin−1x=t∫elog(t)dt=t22+C=(sin−1x)22+C
Answered by liberty last updated on 27/Mar/21
∫eln(sin−1(x))1−x2dx=∫sin−1(x)d(sin−1(x))=2(sin−1(x)2)2+C
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