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Question Number 137148 by nadovic last updated on 30/Mar/21

	Answered by ajfour last updated on 30/Mar/21

	$(3 k g) (4 m / s) = (3 k g) v + (5 k g) V$ $V - v = (0.6) (4 m / s)} \times 3$ $3 v + 5 V = 12 m / s$ $A d d i n g$ $8 V = 19.2 m / s$ $V = 2.4 m / s$ $v = 0 m / s$ $O v e r a l l l o s s i n K i n e t i c e n e r g y$ $= \frac{1}{2} (3 k g) {(4 m / s)}^{2} - \frac{1}{2} (5 k g) {(2.4 m / s)}^{2}$ $= 24 (1 - 0.6) {k g m}^{2} / s^{2}$ $% l o s s i n K_{t o t} = 9.6 J$
	Commented by nadovic last updated on 31/Mar/21

	$T h a n k y o u S i r$
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