Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 137209 by JulioCesar last updated on 31/Mar/21

Answered by bemath last updated on 31/Mar/21

∫ (sec^2 x−1)^2 sec x dx  =∫(sec^5 x−2sec^3 x+sec x )dx  now it easy to solve

$$\int\:\left(\mathrm{sec}\:^{\mathrm{2}} \mathrm{x}−\mathrm{1}\right)^{\mathrm{2}} \mathrm{sec}\:\mathrm{x}\:\mathrm{dx} \\ $$$$=\int\left(\mathrm{sec}\:^{\mathrm{5}} \mathrm{x}−\mathrm{2sec}\:^{\mathrm{3}} \mathrm{x}+\mathrm{sec}\:\mathrm{x}\:\right)\mathrm{dx} \\ $$$$\mathrm{now}\:\mathrm{it}\:\mathrm{easy}\:\mathrm{to}\:\mathrm{solve} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com