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Question Number 137280 by mathlove last updated on 31/Mar/21
Answered by EDWIN88 last updated on 31/Mar/21
⇔y=x(πlnx)=xπlogx(e)⇔y=xlogx(eπ);y=eπ⇒dydx=0.
Answered by mr W last updated on 31/Mar/21
y=xπlnxlny=πlnx×lnx=π⇒y=eπ⇒dydx=0
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