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Question Number 137324 by greg_ed last updated on 01/Apr/21

how to evaluate this one :  P = (1+ (1/(1958)))(1+ (1/(1959)))(1+ (1/(1960)))...(1+ (1/(2017)))(1+ (1/(2018)))(1+ (1/(2019)))  P = ?

howtoevaluatethisone:P=(1+11958)(1+11959)(1+11960)...(1+12017)(1+12018)(1+12019)P=?

Answered by som(math1967) last updated on 01/Apr/21

P=(((1959)/(1958)))(((1960)/(1959)))(((1961)/(1960)))..(((2019)/(2018)))(((2020)/(2019)))  P=((2020)/(1958))=((1010)/(979))

P=(19591958)(19601959)(19611960)..(20192018)(20202019)P=20201958=1010979

Commented by greg_ed last updated on 01/Apr/21

thank u very much, sir som(math1967)

thankuverymuch,sirsom(math1967)

Commented by som(math1967) last updated on 01/Apr/21

welcome

welcome

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