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Question Number 137324 by greg_ed last updated on 01/Apr/21

$$\mathbf{how}\mathbf{to}\mathbf{evaluate}\mathbf{this}\mathbf{one}:$$$$\mathrm{P}=(1+\frac{1}{1958})(1+\frac{1}{1959})(1+\frac{1}{1960})...(1+\frac{1}{2017})(1+\frac{1}{2018})(1+\frac{1}{2019})$$$$\mathbf{P}=?$$

Answered by som(math1967) last updated on 01/Apr/21

$$P=\left(\frac{1959}{1958}\right)\left(\frac{1960}{1959}\right)\left(\frac{1961}{1960}\right)..\left(\frac{2019}{2018}\right)\left(\frac{2020}{2019}\right)$$$$P=\frac{2020}{1958}=\frac{1010}{979}$$

Commented by greg_ed last updated on 01/Apr/21

$$\mathbf{thank}\mathbf{u}\mathbf{very}\mathbf{much},\mathbf{sir}\mathbf{som}\left(\mathbf{math}1967\right)$$

Commented by som(math1967) last updated on 01/Apr/21

$$welcome$$

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