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Question Number 137384 by BHOOPENDRA last updated on 02/Apr/21

Commented by hei last updated on 02/Apr/21

$$ \\ $$

Commented by Dwaipayan Shikari last updated on 02/Apr/21

Sorry that was a mistake  (1/(1.3))+(1/(3.5))+(1/(5.7))+..  =(1/2)(1−(1/3)+(1/3)−(1/5)+(1/5)−(1/7)+....)  =(1/2)

$${Sorry}\:{that}\:{was}\:{a}\:{mistake} \\ $$$$\frac{\mathrm{1}}{\mathrm{1}.\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{3}.\mathrm{5}}+\frac{\mathrm{1}}{\mathrm{5}.\mathrm{7}}+.. \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{3}}−\frac{\mathrm{1}}{\mathrm{5}}+\frac{\mathrm{1}}{\mathrm{5}}−\frac{\mathrm{1}}{\mathrm{7}}+....\right) \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}} \\ $$

Commented by BHOOPENDRA last updated on 02/Apr/21

Ans.is not correct sir ...how can you proceed that way

$${Ans}.{is}\:{not}\:{correct}\:{sir}\:...{how}\:{can}\:{you}\:{proceed}\:{that}\:{way} \\ $$

Commented by BHOOPENDRA last updated on 02/Apr/21

incorrect sir read the question again

$${incorrect}\:{sir}\:{read}\:{the}\:{question}\:{again} \\ $$

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