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Question Number 137412 by oustmuchiya@gmail.com last updated on 02/Apr/21

	Answered by herbert last updated on 02/Apr/21

	$g r a d i e n t o f l_{1} = \frac{2 + 4}{5 + 1} = \frac{6}{6} = 1$ $b u t g r a d o f l_{1} \times l_{2} = - 1$ $g r a d o f l_{2} = - 1$ $e q u a t i o n o f t h e p e r p e n d i c u l a r l i n e l_{2}$ $\frac{y - 5}{x - 2} = - 1$ $y - 5 = - x + 2$ $y = - x + 7$
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