Question Number 137429 by physicstutes last updated on 02/Apr/21
$$\mathrm{A}\:\mathrm{nuclide}\:_{\mathrm{81}} ^{\mathrm{210}} {X}\:\mathrm{decays}\:\mathrm{to}\:\mathrm{another}\:\mathrm{nuclide}\:_{\mathrm{80}} ^{{A}} {Y}\:\mathrm{in}\: \\ $$$$\mathrm{four}\:\mathrm{successive}\:\mathrm{radioactive}\:\mathrm{decays}.\:\mathrm{Each}\:\mathrm{decay} \\ $$$$\mathrm{involves}\:\mathrm{the}\:\mathrm{emmision}\:\mathrm{of}\:\mathrm{either}\:\mathrm{an}\:\mathrm{alpha}\:\mathrm{particle} \\ $$$$\mathrm{or}\:\mathrm{a}\:\mathrm{beta}\:\mathrm{particle}.\:\mathrm{The}\:\mathrm{value}\:\mathrm{of}\:{A}\:\mathrm{is}: \\ $$$$\mathrm{A}.\:\mathrm{120}\:\:\:\:\:\:\:\:\:\:\:\mathrm{B}.\:\mathrm{206} \\ $$$$\mathrm{C}.\:\mathrm{208}\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{D}.\:\mathrm{212} \\ $$
Commented by Dwaipayan Shikari last updated on 02/Apr/21
$$\underset{\mathrm{81}} {{X}}^{\mathrm{210}} \overset{−\alpha} {\rightarrow}{H}_{\mathrm{79}} ^{\mathrm{206}} \\ $$$${H}_{\mathrm{79}} ^{\mathrm{206}} \overset{−\beta_{\mathrm{0}} } {\rightarrow}{Y}_{\mathrm{80}} ^{\mathrm{206}} \:\:{A}=\mathrm{206} \\ $$
Commented by physicstutes last updated on 02/Apr/21
$$\mathrm{sir}\:\mathrm{does}\:\mathrm{this}\:\mathrm{two}\:\mathrm{decay}\:\mathrm{not}\:\mathrm{sum}\:\mathrm{up} \\ $$$$\mathrm{to}\:\mathrm{two}.\:\mathrm{its}\:\mathrm{four}\:\mathrm{they}\:\mathrm{asked}\:\mathrm{for}. \\ $$
Commented by Dwaipayan Shikari last updated on 02/Apr/21
$${Is}\:{there}\:{any}\:\gamma\:{decay}\:{sir}? \\ $$
Commented by physicstutes last updated on 02/Apr/21
$$\mathrm{no}\:\mathrm{just}\:\mathrm{alpha}\:\mathrm{and}\:\mathrm{beta} \\ $$