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Question Number 137466 by Lordose last updated on 03/Apr/21

$$\mathrm{\Omega }={\int }_0^1\frac{{\mathrm{xtan}}^{-1}\left(\mathrm{x}\right)\log \left(\mathrm{x}\right)}{1+{\mathrm{x}}^2}\mathrm{dx}$$

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