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Question Number 137472 by mr W last updated on 03/Apr/21

solve  x^3 −2[x]=5

$${solve} \\ $$$${x}^{\mathrm{3}} −\mathrm{2}\left[{x}\right]=\mathrm{5} \\ $$

Answered by MJS_new last updated on 03/Apr/21

(1)  1<x<2  x^3 =7 ⇒ x=7^(1/3)   (2)  2<x<3  x^3 =9 ⇒ x=9^(1/3)

$$\left(\mathrm{1}\right)\:\:\mathrm{1}<{x}<\mathrm{2} \\ $$$${x}^{\mathrm{3}} =\mathrm{7}\:\Rightarrow\:{x}=\mathrm{7}^{\mathrm{1}/\mathrm{3}} \\ $$$$\left(\mathrm{2}\right)\:\:\mathrm{2}<{x}<\mathrm{3} \\ $$$${x}^{\mathrm{3}} =\mathrm{9}\:\Rightarrow\:{x}=\mathrm{9}^{\mathrm{1}/\mathrm{3}} \\ $$

Commented by mr W last updated on 03/Apr/21

thanks sir!

$${thanks}\:{sir}! \\ $$

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