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Question Number 137523 by SOMEDAVONG last updated on 03/Apr/21

$$\mathrm{L}=\underset{x\to 0}{\lim }\frac{\mathrm{x}!-1}{\mathrm{x}}$$

Answered by Dwaipayan Shikari last updated on 03/Apr/21

$$\underset{x\to 0}{\lim }\frac{\mathrm{\Gamma }(x+1)-1}{x}=\frac{1-\gamma x-1}{x}=-\gamma$$$$\mathrm{\Gamma }(x+1)\sim 1-\gamma x$$

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