Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 137590 by Ñï= last updated on 04/Apr/21

x=1+((π+(π+1)^2 +(π+2)^3 +(π+3)^4 )/(4+5^2 +6^3 +7^4 )) (√(x+2(√(x−1))))+(√(x−2(√(x−1))))=?

x=1+π+(π+1)2+(π+2)3+(π+3)44+52+63+74x+2x−1+x−2x−1=?

Commented by mindispower last updated on 04/Apr/21

(√(x+2(√(x−1))))=(√(((√(x−1))+1)^2 ))=1+(√(x−1)) (√(x−2(√(x−1))))=(√(((√(x−1))−1)^2 ))1−(√(x−1)) 1<x<2 we get 2

x+2x−1=(x−1+1)2=1+x−1x−2x−1=(x−1−1)21−x−11<x<2weget2

Terms of Service

Privacy Policy

Contact: info@tinkutara.com