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Question Number 137594 by Ñï= last updated on 04/Apr/21

(x+(√(x^2 +1)))(y+(√(y^4 +4)))=9  x(√(y^4 +4))+y(√(x^2 +1))=?

(x+x2+1)(y+y4+4)=9xy4+4+yx2+1=?

Answered by bemath last updated on 04/Apr/21

let x=tan t ∧ y=2tan z  ⇒(tan t+sec t)(2tan z+2sec z)=9  (tan t+sec t)(tan z+sec z)=(9/2)  ⇔tan t.tan z+tan t.sec z+sec t.tan z+sec t.sec z=(9/2)  ⇒tan t. 2sec z + 2tan z. sec t = x  ⇒tan t.sec z + tan z.sec t = (x/2)

letx=tanty=2tanz(tant+sect)(2tanz+2secz)=9(tant+sect)(tanz+secz)=92tant.tanz+tant.secz+sect.tanz+sect.secz=92tant.2secz+2tanz.sect=xtant.secz+tanz.sect=x2

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