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Question Number 137597 by bemath last updated on 04/Apr/21

Find the minimum value of x^(2) +y^(2) +z^(2) , subject to the condition 2x+3y+5z=30? \n

Answered by EDWIN88 last updated on 04/Apr/21

Answered by mr W last updated on 04/Apr/21

x^2 +y^2 +z^2  is the squared  distance  from point (x,y,z) to the orgin. so  the minimum of x^2 +y^2 +z^2  is the  squared distance from origin to the  plane 2x+3y+5z−30=0. that is  (((−30)/( (√(2^2 +3^2 +5^2 )))))^2 =((450)/(19))

x2+y2+z2isthesquareddistance frompoint(x,y,z)totheorgin.so theminimumofx2+y2+z2isthe squareddistancefromorigintothe plane2x+3y+5z30=0.thatis (3022+32+52)2=45019

Commented byotchereabdullai@gmail.com last updated on 04/Apr/21

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