Question Number 137597 by bemath last updated on 04/Apr/21 | ||
$$ \\ $$ Find the minimum value of x^(2) +y^(2) +z^(2) , subject to the condition 2x+3y+5z=30? \\n | ||
Answered by EDWIN88 last updated on 04/Apr/21 | ||
Answered by mr W last updated on 04/Apr/21 | ||
$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} \:{is}\:{the}\:{squared}\:\:{distance} \\ $$ $${from}\:{point}\:\left({x},{y},{z}\right)\:{to}\:{the}\:{orgin}.\:{so} \\ $$ $${the}\:{minimum}\:{of}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} \:{is}\:{the} \\ $$ $${squared}\:{distance}\:{from}\:{origin}\:{to}\:{the} \\ $$ $${plane}\:\mathrm{2}{x}+\mathrm{3}{y}+\mathrm{5}{z}−\mathrm{30}=\mathrm{0}.\:{that}\:{is} \\ $$ $$\left(\frac{−\mathrm{30}}{\:\sqrt{\mathrm{2}^{\mathrm{2}} +\mathrm{3}^{\mathrm{2}} +\mathrm{5}^{\mathrm{2}} }}\right)^{\mathrm{2}} =\frac{\mathrm{450}}{\mathrm{19}} \\ $$ | ||
Commented byotchereabdullai@gmail.com last updated on 04/Apr/21 | ||
$$\mathrm{nice}\:\mathrm{shortcut} \\ $$ | ||