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Question Number 137641 by mey3nipaba last updated on 04/Apr/21
Answered by mr W last updated on 05/Apr/21
Commented by mey3nipaba last updated on 05/Apr/21
ohokay.i′msorry.thanksthoughforthesolution.
Commented by mr W last updated on 05/Apr/21
woodaloneinliquid:ρWVW=ρLVLρW=VLVWρL=75100×1.2=0.9woodwithglasinliquid:ρGVG+ρWVW=ρL(VG+VW)(ρG−ρL)VG=(ρL−ρW)VWVG=(ρL−ρW)VWρG−ρL=1.2−0.92.4−1.2×100=25cm3mG=1×ρGVG=1×2.4×25=60g
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